fathers age is 3 times the sum of ages of this 2 children. After 5 years his age will be twice the sum of ages of 2 children. find the age of the father.
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Let the father's age= x
And their son's age= y and z
Condition
x=3(y+z)
x=3y+3z
After 5 years
x+5=2(y+5+z+5)
x+5=2y+10+2z+10
x= 2(y+z)+20-5
x= 2(y+z)+15
3y+3z=2y+2z+15
3y-2y+3z-2z=15
y+z=15
x=3y+3z
x=3(y+z)
x=3(15)=45 years
And their son's age= y and z
Condition
x=3(y+z)
x=3y+3z
After 5 years
x+5=2(y+5+z+5)
x+5=2y+10+2z+10
x= 2(y+z)+20-5
x= 2(y+z)+15
3y+3z=2y+2z+15
3y-2y+3z-2z=15
y+z=15
x=3y+3z
x=3(y+z)
x=3(15)=45 years
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