Math, asked by dipeshbmetha5834, 1 year ago

Fathers age is 32 years older than his son.10 years later ratio of ages of father and son becomes 2:1.What is the present age of father?

Answers

Answered by VemugantiRahul
0
Let the son's age x
Father's age is x+32


10 years later,
Son's age = x+10
Father's age = (x+32)+10= x+42

Given,
(x+42)/(x+10) =2/1
1*(x+42) = 2*(x+10)
x+42= 2x+20
2x - x = 42-20
x = 22, This is son's age

Present age of Father is x+32=22+32=54


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