Math, asked by shashankg6822, 1 year ago

Fathers age is 5 times his son's age. 4 years back the father was 9 times older than son.find the fathers' present age.

Answers

Answered by jish4you
1
Hi Shashank,

Let father's present age be f
Son's present age be s

f = 5s
f-4 = 9(s-4)

solving we get
f=40 yrs
s=8 yrs

Hope it helped.
Let me know if any further doubt.
Cheers !!!
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