Fathers age is three the sum of ages of his two children's after 5 years his age will be twice the sum of age of the two children find the age of father
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let the age of two children be x and y.
father's present age is 3(x+y).
age of children after 5 years= x+5+y+5
= x+y+10
age of the father after 5 years= 2(x+y+10) or 3(x+y)+5
2x+2y+20 = 3x+3y+5
2x-3x + 2y-3y= -20+5
-(x+y) = -15
x+y = 15
3(x+y) = 3(15)
=45
therefore, present age of father is 45.
father's present age is 3(x+y).
age of children after 5 years= x+5+y+5
= x+y+10
age of the father after 5 years= 2(x+y+10) or 3(x+y)+5
2x+2y+20 = 3x+3y+5
2x-3x + 2y-3y= -20+5
-(x+y) = -15
x+y = 15
3(x+y) = 3(15)
=45
therefore, present age of father is 45.
DharshiniDd:
Hope it helps
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