Question

fathers age is three times the sum of ages of his 2 sons . five years later he will be twice the sum of the age of it's two sons . find the present age of father​

Answer 1

Answer:

Present age of Father= 45 yrs

Step-by-step explanation:

Let the age of father be x years and sum of the ages of his children by y years.

After 5 years,

Father's age = (x + 5) years

Sum of ages of his children = (y + 10) years

From the given information, we have:

x = 3y ...(1)

and x + 5 = 2(y + 10)

 x - 2y = 15 ...(2)

From (1) and (2), we have,

3y - 2y = 15  y = 15

 x = 3y = 45

Father's age = 45 years

Answer 2

Let the age of the sons be x and y.

Given that Father’s age is three times the age of his two sons.

Therefore, present age of father is 3(x+y)

Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

3(x+y)+5 = 2(x+5+y+5)

3x+3y+5 = 2x+10+2y+10

3x+3y+5 = 2x+2y+20

3x-2x+3y-2y = 20–5

x+y = 15

Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

Thus the age of the father is 45.