Fathrs age is five times his sons age,four years back father was 9 times olderthan his son ,find his present age
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let son's age be x
let father's age be 5x
FOUR YEARS BACK:
son's age : x-4
father's age : 5x-4
5x-4 = 9(x-4)
5x-4= 9x - 36
9x- 5x= 36-4
4x=32
x=8
so therefore son's age is 8
father's age is 5×8 = 40 years
let father's age be 5x
FOUR YEARS BACK:
son's age : x-4
father's age : 5x-4
5x-4 = 9(x-4)
5x-4= 9x - 36
9x- 5x= 36-4
4x=32
x=8
so therefore son's age is 8
father's age is 5×8 = 40 years
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