Fatima wants to mail three parcels to three village schools. She finds that the postal charges are Rs 20, Rs 28 and Rs 36, respectively. If she wants to buy stamps only of one denomination, what is the greatest denomination of stamps she must buy to mail the three parcels?
Answers
Answered by
203
you need to take the hcf
hcf(28,20)=
28=20×1+8
20=8×2+4
8=4×2+0
HCF of 28 and 20 is 4
Hcf (36 and 4)=4
.°. the denomination is 4
hcf(28,20)=
28=20×1+8
20=8×2+4
8=4×2+0
HCF of 28 and 20 is 4
Hcf (36 and 4)=4
.°. the denomination is 4
Answered by
86
Find the prime factors:
20 = 2² x 5
28 = 2² x 7
36 = 2² x 3²
Find the HCF:
HCF = 2² = 4
Answer: The smallest denomination is Rs 4.
Additional information:
Find the number of stamps that she will need to buy:
Rs 20 parcel = 20 ÷ 4 = 5 stamps
Rs 28 parcel = 28 ÷ 4 = 7 stamps
Rs 36 parcel = 36 ÷ 4 = 9 stamps
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