Question

fatorise 15x^4+3x^2-18​

Answer 1

Step-by-step explanation:

Let x^2 be y .

Now ,

15y^2 +3y-18

=15y^2+18y-15y-18

=3y(5y+6)-3(5y+6)

=3(y-3)(5y+6)

=3(x^2-3)(5x^2-6)

Answer 2

Answer:

$\bold\red{ 3(x + 1)(x - 1)(5 {x}^{2} + 6)}$

Step-by-step explanation:

Given,

$15 {x}^{4} + 3 {x}^{2} - 18$

Let's take ,

${x}^{2} = y$

Therefore,

we get,

$= 15 {y}^{2} + 3y - 18$

Splitting the middle term,

we get,

$= 15 {y}^{2} + (18y - 15y) - 18 \\ \\ = 15 {y}^{2} - 15y + 18y - 18$

Taking common terms,

we get,

$= 15y(y - 1) + 18(y - 1) \\ \\ = (y - 1)(15y + 18)$

Now,

putting the value of

$y = {x}^{2}$

we get,

$= ( {x}^{2} - 1)(15 {x}^{2} + 18) \\ \\ = \bold{ 3(x + 1)(x - 1)(5 {x}^{2} + 6)}$