Question

Fatorise the middle term

x^2-11x-80

Answer 1

Hey mate,.

=> x² - 11x - 80 = 0

=> x² - 16x + 5x - 80 = 0

=> x(x - 16) + 5(x - 16) = 0

=> (x + 5)(x - 16) = 0

Thus x = -5 and x = 16

Hope it will help you

Answer 2

Hey Dear !

=) x² - 11x - 80 = 0

x² - 11x - 80 = 0=> x² - 16x + 5x - 80 = 0

x² - 11x - 80 = 0=> x² - 16x + 5x - 80 = 0=> x(x - 16) + 5(x - 16) = 0

x² - 11x - 80 = 0=> x² - 16x + 5x - 80 = 0=> x(x - 16) + 5(x - 16) = 0=> (x + 5)(x - 16) = 0

x² - 11x - 80 = 0=> x² - 16x + 5x - 80 = 0=> x(x - 16) + 5(x - 16) = 0=> (x + 5)(x - 16) = 0Thus x = -5 and x = 16

Hope , It Helps .