Question

Fatorise
x^3-23x^2+142x-120 ​

Answer 1

Answer:

 

x  3 −23x  2  +142x−120

=x  3  −x  2  −22x  2  +22x+120x−120

=x  2  (x−1)−22x(x−1)+120(x−1) =(x−1)(x  2  −22x+120)

=(x−1)[x  2 −10x−12x+120]

=(x−1)[x(x−10)−12(x−10)]

=(x−1)(x−10)(x−12)

Step-by-step explanation: