Question

Favorite value of k the quadratic equation 2xq + k x + 3 equal to 0 has equal roots

Answer 1

For a given polynomial $p(x) = 2x^2 + kx + 3$,

As the roots are equal, the discriminant will be 0.

The formula for discriminant is $D = b^2 - 4ac$ where,

a = coefficient of the first term,

b = coefficient of the second term,

c = constant value

From the equation, we can see that $a = 2, b = k, c =3$.

Putting the values in the formula, we get,

$D = (k)^2 - 4(2)(3)$

$0 = k^2 - 4(2)(3)$                          [ as it is given that D = 0 ]

$0 = k^2 - 24$

$24 = k^2$

$k = 2\sqrt{6}$

Hope this helps :)