Chemistry, asked by jayasimhaj38, 5 hours ago

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In how many ways can X give Rs. 500 to Y using only Rs. 100 and Rs. 20 notes, with the condition that she has only 16 notes of Rs. 20, and being asked to use the notes of both the denominations?
a.2
b.4
c.3
d.6​​

Answers

Answered by AratrikaGhosh56
1

Explanation:

Let's say we have denote the no.of notes of Rs.50 as F, Rs.100 as H, Rs.10 as T, and Re.1 as

O.

Hence 50F+100H+10T+0=107

A cursory observation leads to:

H<= 1; F<=2; T<= 10; 0<=107

Case 1

H=1 => 50F+10T+0=7 => 0=7; T=F=0; H=1

(Combination 1)

Case 2

H=0 => 50F+10T+O= 107

Sub-Case 1

F=2 => 10T+0=7=> T=0; O=7; F=2; H=0

(Combination 2)

Sub-case 2

F=1 => 10T+O=57=> T=5,4,3,2,1,0 each will give rise to one final combination (6 combinations

H=0; F=1;)

F=0 => 10T+0=107 => T-10,9,...,1,0 will give rise to 10 possible combinations (10 combinations

H=0; F=0)

Hence overall 1+1+6+10=18 combinations or 18 ways to make the payment

Answered by harini270366
1
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