Question

FBEC and ABG are straight lines. ABCD is a parallelogram. AEC is an isosceles right-angled triangle. Find angle n

pls show the answers with full steps would help a lot :)​

Answer 1

$\huge \mathcal {\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}{!}}}$

Angle DFE = AFB = 35° ( Opposite angles)

Angle ECB = BAF = 75° (Opposite angles of parallelogram )

in ∆AFB

Two angles are 35° and 75° . Since Sum of angles be 180° . So third angle

ABF = 180°- (75°+35°) = 70°

HOPE SO IT WILL HELP....