Fbina borows 12500 at 12% per annum for 3 years at simple interest and radha borrows the same amount for the same time period at 10% per annu,m compounded anuunaly .Who pays more interest and by how much?
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Answers
Given,
- Principal = ₹12500
- Rate of Interest = 12%
- Time = 3 years
We know that :
Given,
- Principal = ₹12500
- Rate of Interest = 10%
- Time = 3 years
We Know that :
Now Compound Interest Find :
⇒Amount - Principal
⇒16637.50 - 12500
⇒₹4137.50
∵Compound Interest is less than Simple Interest that means Fabina paid more interest than Radha.
⇒4500 - 41375
⇒₹362.50(Answer)
Case 1:
- For Fabina:
Given:
- P = ₹ 12,500
- R = 12%
- T = 3 Years
Formula used here:
- SI = P × R × T/100
Putting the values according to the given formula:
➠ 12500 × 12 × 3/100
➠ 125 × 12 × 3
➠ Rs.4,500
Case 2:
- For Radha:
Given:
- P = ₹ 12,500
- R = 10%
- T = 3 Years
Formula used here:
- Amount = P(1 + R/100)^n
Putting the values according to the given formula:
➠ 12,500(1 + 10/100)^3
➠ 12,500(1+ 1/10)^3
➠ 12,500(11/10)^3
➠ 12,500 × 11/10 × 11/10 × 11/10
➠ 25 × 1331/2
➠ Rs. 16637.50
Now, Need To Find:
- New Compound Interest = ?
Formula used here:
- Amount - Principal
Putting the values according to the given formula:
➠ 16637.50 - 12500
➠ Rs. 4137.50
Now, we can say that compound interest is less than simple interested it means Fabina paid more interest than Radha.
➠ 4500 - 41375
➠ Rs. 362.50 (Your Answer)
Here:
- P is used for Principal.
- R is used for Rate of Interest.
- T is used for Time.
- SI is used for Simple Interest.