Question

fctorize the quadratic equation
3x²-12x+16=0

Answer 1

Answer:

• Solve it through middle term splitting method.

= 3x²-12x+16=0

= 3x² - (8+6)x + 16

= 3x² - 8x-6x + 16

= x(3x- 8)-2(3x- 8)

= (3x - 8) ( x - 2)

Thus , the factors are (3x - 8) ( x - 2)

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Answer 2

Answer:

Step-by-step explanation:

According to the Quadratic Formula,  x  , the solution for  ax2+bx+c = 0  , where  a, b  and c  are coefficients, is given by :

       x = -b ±√ b² - 4ac / 2a

So in equation 3x² - 12x + 16 = 0

a= 3, b = -12, c = 16

x = -(-12) ± √ (-12)² - 4(3)(16) / 2 * 3

  = 12 ± √144 - 192 / 6

  = 12 ±√-48 / 6

   = 12 ±√16(-3) / 6

   = 12 ± 4√-3 / 6

    = 12/6 ± 4/6(i√3)  (∵ i = √-1)

    = 2 ± 2/3(i√3)

    = 2 ± 2i/√3

=> x = 2 + 2i/√3, x = 2 - 2i/√3