Fe(OH) + H₂O2
> 2
2 Fe(OH)₂redox reaction
in basic meduum
brief explanation please
Answers
Answer:
This is a redox reaction and it helps to split it up into the oxidation and reduction half reactions…
Oxidation of Fe^(2+) to Fe^(3+)
(1) Fe(OH)2 + H2O → Fe(OH)3 + H^(+) + e(-)
Reduction of oxygen…
(2) 2 H2O + O2 + 4 e^(-) → 4 OH^(-)
Add 4 x (1) + (2) to cancel out the electrons
(3) 4 Fe(OH)2 + 4 H2O + 2 H2O + O2 + 4 e^(-) → 4 Fe(OH)3 + 4 H^(+) + 4 e(-) + 4 OH^(-)
Also on RHS, 4 H^(+) + 4 OH^(-) → 4 H2O
The 4 H2O then cancels from each side of the equation to give…
(4) 4 Fe(OH)2 + 2 H2O + O2 → 4 Fe(OH)3
NOTE: you would see a gelatinous red/brown ppt in a test tube which turns into a red/brown powder after a few minutes. This would be rust, Fe2O3...
2 Fe(OH)3 → Fe2O3 + 3 H2O
Fe(OH)3 is sometimes referred to a “hydrated ferric oxide” or Fe2O3.3H2O
Explanation: