Fe(s)+cd2+(aq) =Fe2+(aq) +cd(s)
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Answer:
k=3.23×10^13
Step-by-step explanation:
Fe(s)+cd^2+(aq)=Fe^2+(aq)+CD(s)
>>E°fe^2+/Fe=(-0.44v)
>>E°cell=E°fe^2+/Fe+E°cd^2+/CD
=0.44-0.40=.0.4v
>>E°=0.0592/n. log K
>>Log K=nE°cell/0.0592
=2×0.4/0.0592
>>Log K=13.51
>>. K=3.23×10^13
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