Fe2o3+2al⟶al2o3+2fe. Calculate the mass of iron metal
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Answer:
according to the law of mass
weight of reactants = weight of products
weight of fe203+ weight of 2al =weight of al2o3 + weight of 2fe
weight of (fe2o3 +2al -al2o3)= weight of 2fe
2*56+3*16 +2*27-(2*27+3*16)=weight of 2fe
112+48 +54-54-48=weight of fe
112 =weight of fe
one more method is
as the given chemical reaction is balances
there are 2 moles of fe
mass of 1 mole of fe =56g
mass of 2 moles of fe = 56 *2 =112 g
Explanation:
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