fe2o3+3co gives 2fe+3co2 if reaction is carried out by mixing 30gm of fe2o3 and 10gm of CO
1:calculate weight of iron produced
2 what volumr of co2 is produced at 30C and 730mm peessure
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Answer:
From,balanced equation,
160 g Ferric oxide requires 84 g of CO.
For 30g Fe2O3 ,15.75 g CO is required.
But only 10 g is available.
Therefore,CO is the limiting reagent
From 84 g CO we get 112g Fe
So from 10g we get 13.3 g
For part 2 of the question,
10 g CO means 0.36 moles
From balanced equation,it is clear that,
3 moles CO releases 3 moles CO 2
Therefore,0.36moles CO2 is released.
Using PV=nRT
We get
P=700*133Pa ,R=8.314(SI)and T=303K
V=9.741mL
Hope it helps you!!
Sorry I couldn't upload images.
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