Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq)
A solution is made containing an initial [Fe3+] of 2.7×10−4 molL−1 and an initial [SCN−] of 8.5×10−4 molL−1 . At equilibrium, [FeSCN2+]= 1.8×10−4 molL−1
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Part A
Calculate the value of the equilibrium constant (Kc)
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Express your answer using two significant figures.
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part a this bus driver
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PART a. The value of Equilibrium is 6.79J.
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