Question

Fe3O4 + 4CO  3Fe + 4CO2
Fe is produced according to the above equation. If
efficiency of the reaction is 80%, then how much
Fe3O4 should be treated to obtain 11.2 g Fe?

Answer 1

Answer:

19.33 gm of fe3o4 is required

Explanation:

let's explain this,

in the given equation 1mole of Fe3o4 gives 3 moles of Fe

I.e. 232gm of fe3o4 gives 168gm of iron

in the above statement applicable when efficiency of reaction is 100%

but in the given problem efficiency is 8o%

therefore

100%efficiency of rxn------------168gm

80%efficiency of rxn--------------?

we get 80×168/100=134.4gm of fe is obtained from 232gm of fe3o4.

therefore,134.4gm of fe formation would take 232gm of fe3o4 under the new run

11.2gm of fe formation would take ?gm of fe3o4

134.4gm of fe-------------232gm of fe3o4

11.2gm of fe---------------?

after solving we get answer of 19.33gm

therefore answer is 19.33gm of fe3o4 is required

I hope you understand this

Answer 2

Explanation:

here is ur answer mate

rate accordingly