Chemistry, asked by aditya397057, 1 year ago

fe3o4 +4co --->3fe +4co2. efficiency of reaction is 80 % then how much fe3o4 should be treated to obtain 11.2g Fe​

Answers

Answered by kobenhavn
5

Answer: 57.8 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Fe_3O_4+4CO\rightarrow 3Fe+4O_2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=-\frac{11.2}{56}=0.2moles

According to stochiometry:

1 mole of Fe is produced by=  1 mole of Fe_3O_4

Thus 0.2 moles of Fe is produced by= \frac{1}{1}\times 0.2=0.2moles of [tex]Fe_3O_4

But as efficiency of the reaction is 80%, the amount of Fe_3O_4 required will be is=\frac{100}{80}\times 0.2=0.25moles

Mass of Fe_3O_4 =moles\times {\text {molar mass}}=0.25\times 231.5=57.8g

Thus 57.8 grams of Fe_3O_4 should be treated to obtain 11.2 grams

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