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Find the domain and the range of the
real function, f(x) = 1\x+3
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Answer:
given : f(x) = 1/x+3
to find domain and Range
x + 3 ≠ 0
x ≠ -3
Domain = { R - ( -3 ) }
let y = 1/x+3
=> y(x+3) = 1
=> x + 3 = 1/y
=> x = 1/y - 3
y ≠ 0
Range = {R - ( -3 , 0 ) }
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