fel z + N H ₂ OH - Fe(OH)2 + NHO
Lo Balance thes Egn
Answers
Answered by
2
Answer:
E
cell
∘
=E
Fe
2+
/Fe
3+
∘
+E
Ag
+
/Ag
∘
=−0.771+0.799=0.028 volt
At equilibrium, E
cell
=0
0=E
cell
∘
−
1
0.0591
log
[Fe
2+
][Ag
+
]
[Fe
3+
]
=E
cell
∘
−0.0591log
[Ag
+
]
1
[Ag
+
]=0.34
logK=
0.0591
nE
∘
;K=3.0.
Explanation:
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