Question

Fencing the compound of a house cost ₹ 4930. If the rate is ₹ 85 per metre, find the perimeter of the compound. If the breadth is 10 metre, find its length.

Answer 1

Perimeter of compound
$\frac{total \: cost}{rate}$
ie,
$= \frac{4930}{85} \\ = 58 \: m$

$perimeter \: = 2(l + b) \\ = 2(l \: + 10) \\ = 2l + 20 = 58 \\ 2l \: = 58 - 20 = 38 \\ l = 38 \div 2 \\ = 19$


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Answer 2

Hi friend, Harish here.

Here is your answer:

Given that,

Cost of fencing per meter = Rs 85.

Cost of fencing whole house = Rs 4930

Breadth = 10m.

To  find,

Perimeter & Length of the rectangle.

Solution,

Cost of fencing Whole compound = Cost of fencing per meter × Perimeter.

⇒ $4930 = 85\times perimeter$

⇒ $perimeter= \frac{4930}{85}$

⇒ $Perimeter = 58\ m.$

We know that,

Perimeter = 2( length + bredth).

Let length be x.

Then,

$58 = 2(x + 10)$

⇒ $x+10=\frac{58}{2} = 29$

⇒ $x = 29 -10 = 19.$

Therefore Length is 19 cm & Perimeter is 58 cm.
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Hope my answer is helpful to you.