Question

fencing the compound of a house cost rupees 5452 if the rate is rupees 94 per metre find the perimeter of the compound if the breadth is 10 metre find its length.​

Answer 1

Answer :

• Perimeter of the compound = 58m
• Length of compound = 19m

Given :

• Fencing the compound of house cost rupees 5452
• If the rate is rupees 94 per metre
• Breadth of compound is 10m

To find :

• Perimeter of the compound
• Length of compound

Solution :

To find the perimeter of compound and length of compound , we must use the perimeter of rectangle formula

Given,

• Compound of house cost is 5452 ₹
• Fencing per one metre = 94 ₹

Finding the perimeter of the compound :

➞ 5452/94

➞ 2726/47

➞ 58m

Perimeter of the compound is 58m.

Finding the length of compound :

To find the length of compound, we must use the formula of perimeter of rectangle

• Let the length of compound be l

We know that,

• Perimeter of compound = 2(l + b)

Where ,

• l is length
• b is breadth

➞ Perimeter of compound = 2(l + b)

➞ 58 = 2(l + 10)

➞ l + 10 =58/2

➞ l + 10 = 29

➞ l = 29 - 10

➞ l = 19m

Length of compound is 19m

Hence,

• Perimeter of the compound = 58m
• Length of the compound = 19m

Verification :

• Perimeter of the compound = 2(l + b)

Where ,

• l is length (19m)
• b is breadth (10m)
• Perimeter is 58m

Taking RHS

➞ Perimeter of the compound = 2(l + b)

➞ 58 = 2(19 + 10)

➞ 58 = 2(29)

➞ 58 = 58

LHS = RHS

Hence , Verified

Answer 2

Question:

fencing the compound of a house cost rupees 5452 if the rate is rupees 94 per metre find the perimeter of the compound if the breadth is 10 metre find its length.

Given:

Cost Of Fencing A House Is ₹5452.

Per Meter Is ₹94.

Breadth Is 10m.

To Find:

Length of the compound.

Solution:

Firstly, We Will Find The Perimeter Of The Compound.

$\leadsto\bf \cancel\frac{5452}{94} \: ^{58} \\ \\ \bf\leadsto 58m.$

So, The Perimeter Of The Compound Is 58m.

Now, We Will Find the Length Of Compound.

$\sf{perimter \: of \: rectangle = 2(l + b)} \\ \sf : \implies 58m = 2( l+ 10) \\ \sf : \implies58 = 2l + 20 \\ \sf : \implies38 = 2l \\ \sf : \implies \cancel \frac{38}{2} \: ^{19} = l \\ \sf : \implies19m = l$

Final Answer:

$\huge \bf{19m = l}$

To Know More:

• Area Of Rectangle Is L×B
• Rectangle Is a Quadrilateral.
• Volume Of Rectangle Is Length × Width × Height.
• Rectangle Is A 2D shape.
• 3D shape of rectangle is Known As Cuboid.