Question

fencing the compound of a house cost rupees 5452 if the rate is rupees 94 per metre find the perimeter of the compound if the breadth is 10 metre find its length.
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Answer 1

Answer:

19 m

Step-by-step explanation:

Let perimeter be x,

94*x = 5452

x = 58 m

now perimeter of rectangle = 2( l + b )

                                         58 = 2( l + b )

                                         29 = l + b

                                             l = 29 - 10     ( b=10 )

                                             l = 19 m

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Answer 2

Answer:-

• length = 19m
• perimeter = 58m

Given:-

• Total cost of fencing = rupees 5452 .
• breadth = 10m
• cost per meter = 94

Explaination:-

$\tt : \mapsto\red{\boxed{\bf \: perimeter = \frac{total \: cost \: }{cost \: per \: meter \: } }}$

$: \mapsto \tt \bf \: perimeter \: = \frac{5452}{94}$

$\tt : \mapsto \boxed{ \red{\bf \: perimeter \: = 58m}}$

As , perimeter = 2(l+b)

$\tt : \mapsto \bf \: 58 = 2(l + 10)$

[Given , breadth = 10 m ]

$\tt : \mapsto \bf \: 58 = 2l + 20$

$\tt : \mapsto \bf \: 2 \times length = 38$

$\tt \red{\boxed{ : \mapsto \bf \: length \: = 19m}}$

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