Question

Fencing the compound of a house costs ₹ 5452. If the rate is₹94 per metre find the perimeter of the compound. If the breadth is 10 m find its length

Answer 1

Answer:

5452÷94=58 its ur peri

2(l+b) is formulae of perimeter

2(l+10)=58

l+10=29

L=19//

hope got it..

Answer 2

$l = 19m$

Step-by-step explanation:

$perimeter \: = \frac{5452}{94 - 58}m \\ 2(l + b) = 58 \\ 2(l + 10) = 58 \\ l + 10 = \frac{58}{2} = 29 \\ l = 29 - 10 = 19m \\ l = 19m$