Question

fencing the compound of a house courts rupees 5452 if the rate is rupees 94 per metre find the perimeter of the compound if the breadth is 10 m find its length​

Answer 1

Answer:

The perimeter of the compound is 58 m and the length of the compound is 19m.

Step-by-step explanation:

Let the perimeter of the compound be $x$. Since the fencing cost 94 per meter and the total cost for fencing was 5452 rupees, we have

$5452=94\times x=94x\\\\\implies x=\dfrac{5452}{94}= 58$

So the perimeter is 58 meters. It is also given that the breadth of the compound is 10 m.

The perimeter of a rectangle with a length $l$ and a breadth $b$ is given by the formula,

$P=2(l+b)$

Substitute the values of perimeter and breadth in the equation,

$\implies 58=2(l+10)\\\\\implies 58=2l+20\\\\\implies 2l=58-20\\\\\implies 2l=38\\\\\implies l=\dfrac{38}{2}=19$

The length of the compound is 19 meters.

Answer 2

QUESTION :

• fencing the compound of a house courts rupees 5452 if the rate is rupees 94 per metre find the perimeter of the compound if the breadth is 10 m find its length

GIVEN :

• fencing the compound of a house courts rupees 5452 if the rate is rupees 94 per metre

• compound if the breadth is 10 m

TO FIND :

• WHAT IS THE LENGTH = ?

SOLUTION :

Cost = rs 5452

perimeter = cost of fencing / rate of fencing

so perimeter = 5452 /94 = 58 cm

perimeter = 2 ( length × breadth )

58 = 2 ( l + 10)

29 = l + 10

so, length = 19 m

MORE INFORMATION :

perimeter of rectangle = 2 ( length × breadth)

perimeter of square = 4 × side

perimeter of traingle = a + b + c