Question

Fend the distance
dutance betwen the co ordinate of the point A (2, 3) and b (10,2​

Answer 1

Answer:

Let the depth of the tank be h.

Given:-

Volume of tank = 6160m

3

Radius of tank = 14m

As we know that, volume of tank is given as-

V= πr

2

h

Therefore,

Volume of tank

=

πr

2

h

⇒

7

22

×

(14) 2

6160

⇒ 616h= 6160

⇒ h=

616

6160

=

10m

Hence the depth of the tank is 10m

Now again as we know that the curved surface area of cylinder is given as-

A= 2πrh

Therefore,

curved surface area of tank

=

2×

7

22

×

14×

10=

880m

2

Given that the cost of painting is Rs.3 per m

2

.

Therefore,

Cost of painting the curved outer surface of tank

=

3×

880=

Rs.2640

Hence the cost of painting the curved outer surface is Rs.2640.

Answer 2

Topic:-

Co- Ordinate System

Question :-

Find the distance between the c ordinates of the point A(2,3) and B(10,2)

Solution:-

A=(2,3)

B = (10,2)

We Know that

x1=2 , y1=3

x2=10 , y2=2

By Applying Distance Formula we get

$= \sqrt{(2 - 10 {)}^{2} +(3 - 2 {)}^{2} }$

$= \sqrt{( - 12 {)}^{2} + (1 {)}^{2} }$

$= \sqrt{144 + 1}$

$\\ \\ \\ = \sqrt{145} \: \: units$

Answer:-

$\sqrt{145} units$

Formula Used:-

$\sqrt{(x1 - x2 {)}^{2} + (y1 - y2 {)}^{2} }$

More Information :-

Distance formula:-

$\bf\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Centroid formula:-

$\bf\dfrac{x_1+x_2+x_3}{3},\bf\dfrac{y_1+y_2+y_3}{3}$

Section formula Internal division

$\bf\dfrac{mx_2+nx_1}{m+n}, \bf\dfrac{my_2+ny_1}{m+n}$

Section formula External division

$\bf\dfrac{mx_2-nx_1}{m-n}, \bf\dfrac{my_2-ny_1}{m-n}$