Feso4 undergoes decomposition
2 feso4(s) = fe2O3(s) + SO2(g) + SO3(g)
At 1 atm & 273K if (7.6gm) FeSO4
tаkеи THEN
The volume occupied by the gases at
1atm 273K -
Answers
Answered by
3
The volume occupied by the gases at 1 atm at 273 K is 0.0748
Explanation:
The chemical equation given in the question is:
2 FeSO₄ (s) → Fe₂O₃ (s) + SO₂ (g) + SO₃ (g)
The gaseous mixture in the given reaction = SO₂ (g) + SO₃ (g)
The volume of the gaseous mixture is given by the formula:
Volume = (Mass) ÷ (Density)
On substituting the values, we get,
Volume = (64 + 80) ÷ (1920 + 2.63)
∴ Volume = 0.0748
Answered by
0
Answer:
2FeSo4(s) -------------- Fe2O3(s) +SO2(g) +SO3(g)
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