Question

Fest side is 20 cm sides of a triangle are in the ratio 3: 2:5 and its perimeter is 30 cm. The length of 16) 15 cm (c) 10 cm (d) 12 cm ​

Answer 1

⇒Let x be common ratio

∴ Sides of triangle will be: 12x,17x and 25x

⇒Perimeter =540 cm(given)

⇒12x+17x+25x=540 cm,

⇒54x=540 cm

⇒x=10 cm

∴ Sides of triangle: a=120,b=170,c=250cms

⇒2S=540

⇒S=270 cm

A= s(s−a)(s−b)(s−c)

= 270(270−120)(270−170)(270−250)cm2

= 270×150×100×20 cm 2

=9000 cm 2

Answer 2

Let x be common ratio

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms⇒2S=540

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms⇒2S=540⇒S=270 cm

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms⇒2S=540⇒S=270 cmA= s(s−a)(s−b)(s−c)

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms⇒2S=540⇒S=270 cmA= s(s−a)(s−b)(s−c)= 270(270−120)(270−170)(270−250)cm2

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms⇒2S=540⇒S=270 cmA= s(s−a)(s−b)(s−c)= 270(270−120)(270−170)(270−250)cm2= 270×150×100×20 cm 2

Let x be common ratio∴ Sides of triangle will be: 12x,17x and 25x⇒Perimeter =540 cm(given)⇒12x+17x+25x=540 cm,⇒54x=540 cm⇒x=10 cm∴ Sides of triangle: a=120,b=170,c=250cms⇒2S=540⇒S=270 cmA= s(s−a)(s−b)(s−c)= 270(270−120)(270−170)(270−250)cm2= 270×150×100×20 cm 2=9000 cm 2