Math, asked by yashdeep75, 1 year ago

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Answered by tahseen619
2
x = 2 - \sqrt{3} \\ \frac{1}{x} = \frac{1}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ \frac{2 + \sqrt{3} }{ {(2)}^{2} - {( \sqrt{3} )}^{2} } \\ \frac{2 + \sqrt{3} }{4 - 3} \\ \frac{1}{x} = 2 + \sqrt{3} \\ - \frac{1}{x} = - 2 - \sqrt{3}
 {(x - \frac{1}{x} )}^{3} \\ {(2 - \sqrt{3} - 2 - \sqrt{3} )}^{3} \\ {( - 2 \sqrt{3} )}^{3} \\ - (2 \times 2 \times 2 \times \sqrt{3} \times \sqrt{3} \times \sqrt{3} ) \\ - (8 \times 3 \times \sqrt{3} ) \\ - 24 \sqrt{3}
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