Question

ffind the probability of distribution of the numbers of times a total of 9 appears in two throw of two dice ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:



Step-by-step explanation:

two dice are thrown so P(S)=36

chances of getting 9 are (4,5) (6,3) (5,4) (3,6)

P(A)=4

PROBABILITY=P(A)/P(S)

                        =4/36

                        =1/9