fibd general solution?
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mattesonpanther:
not sure how to do this
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thitha = 45 degree is your answer
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2cos²theta+√2 sin theta=2
√2(√2cos²theta)+sin theta=2
√2(1-sin² theta)+sin theta =√2
√2-√2sin² theta + sin theta = √2
-√2 sin² theta +sin theta =0
√2 sin² theta - sin theta=0
√2 sin² theta = sin theta
sin² theta= sin theta /√2
sin theta=1/√2
theta=45˙
√2(√2cos²theta)+sin theta=2
√2(1-sin² theta)+sin theta =√2
√2-√2sin² theta + sin theta = √2
-√2 sin² theta +sin theta =0
√2 sin² theta - sin theta=0
√2 sin² theta = sin theta
sin² theta= sin theta /√2
sin theta=1/√2
theta=45˙
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