Question

Fibd the ans for this
Y=log√(sinx)

Answer 1

Y=log√sinx

y=1/2logsinx

dy/dx=1/2.d/dx(logsinx)

dy/dx=1/2.1/sinx .(cosx)

=1/2(cotx)

Answer 2

Answer:

$y=log(\sqrt{sinx} )\\\\y=\dfrac{1}{2} \log({sinx} )\\\\\dfrac{dy}{dx} =\dfrac{1}{2} .\dfrac{1}{\sin x} .\cos x\\\\\dfrac{dy}{dx} =\dfrac{1}{2}\cot x$