Fid the total surface area of the following solids.
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Answer:
7(5*12)+2(5*5)+2(15*5)
= 7*60+2*25+2*75
=420+50+150
=620
then , total surface area of the following solid is 620 cm²
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Step-by-step explanation:
So ,
In following figure...
It can be divided into 4 cuboids of similar dimensions ..
Therefore,
TSA of 1 cuboid =2(lb+bh+lh)
=>2(12×5+5×5+12×5)
=>2(60+25+60)
=>2(120+25)
=>2(145)
=>290cm² ( Of 1 cuboid..)
Therefore all other cuboids having same dimensions have a surface area equal to this cuboid...
Therefore
Total Surface area of 4 cuboids=4×290cm²
=>1160cm²
The answer is= 1160cm²..
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