Math, asked by farharazvi, 1 year ago

Fid the value of root 5 +root 2×root 5-root 2

Answers

Answered by paryuljain23
3

√5 + √2 * √5 - √2

√7 * √3

√21


farharazvi: Its wrong
Answered by Anonymous
6
 (\sqrt{5 } + \sqrt{2} )<br /> \times ( \sqrt{5} - \sqrt{2} )
Using Identity
 {x}^{2} - {y}^{2} = (x + y)(x - y)
Here ......

x denotes  \sqrt{5} and y denotes  \sqrt{2}

Now.........

 (\sqrt{5 } + \sqrt{2} ) \times ( \sqrt{5} - \sqrt{2} ) \\ = &gt; { (\sqrt{5} )}^{2} - {( \sqrt{2}) }^{2} \\ = &gt; 5 - 2 \\ = &gt; 3

kakkerisunil: Hi
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