Fidn three solutions of linear equation 15x + 12y = 27 in two variables. Also draw its graph.
Answers
Answered by
43
The solution of the equation by trial and error method
i) when x = 1 and y = 1
15(1) + 12(1) = 27
27 = 27
So, the solution is (1,1)
ii) When x = 0.2 and y = 2
15(0.2) + 12(2) = 27
3 + 24 = 27
27 = 27
So, the solution is (0.2, 2)
iii) When x = 2 and y = -0.25
15(2) + 12(-0.25) = 27
30 - 3 = 27
27=27
So the solution is (2, -.0.25)
Check the graph in the image
i) when x = 1 and y = 1
15(1) + 12(1) = 27
27 = 27
So, the solution is (1,1)
ii) When x = 0.2 and y = 2
15(0.2) + 12(2) = 27
3 + 24 = 27
27 = 27
So, the solution is (0.2, 2)
iii) When x = 2 and y = -0.25
15(2) + 12(-0.25) = 27
30 - 3 = 27
27=27
So the solution is (2, -.0.25)
Check the graph in the image
Attachments:
Similar questions