field is 75 m long and 32 m wide two 3 m wide roads are constructed in the centre of the field one parallel to its length and the other parallel to is breadth then area of remaining field will be
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Answer:
Length of the rectangular lawn=75m
Breadth of the lawn=60m
Width of the road=4m
Area of the road(ABCD) parallel to the length of the lawn = 75m×4m
=300m
2
Area of the road(EFGH) parallel to the breadth of the lawn = 60m×4m
=240m
2
Area of the common area in both ABCD and EFGH = 4m×4m
=16m
2
Total area of both the rectangular roads = 300+240−16
=524m
2
Cost of gravelling the roads per m
2
= Rs.4.50
Cost of gravelling the roads for 524m
2
=4.50×524
=2358
Cost of gravelling the road is Rs.2358
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