Question

Fifteen balls are numbered from 1 to 15 and one ball is chosen at random. Find the probability of choosing a ball with: a) 2-digit number b) number divisible by 3

please answer
no spam or I'll report​

Answer 1

$\huge\underline\mathfrak\pink{Answer⤵}$

a) 2 digit number

Solution:-

Total numbers=15

Number of 2 digits=6

Probability=15/6

Probability=2.5%

b)Number divisible by 3

Solution:-

Total numbers=15

Number of 3 multiples=5

Probability=15/5

Probability=3%

Hope it helps..

Keep smiling..☺

_______❤______

$\huge\underline\mathtt\pink{Know\: More:-}$

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true.

Answer 2

Answer:

◩ a) probability of getting 2-digit numbers is :

$\sf \to \frac{2}{5}$

◩ b) Probability of getting numbers divisible by 3 is :

$\sf \to \frac{1}{3}$

Step-by-step explanation:

Given that, 15 balls are named from 1 to 15 where a random ball is being chosen.

❐ In case of (a) :

➡ 2-digit numbers between 1 to 15 are :

= 10, 11, 12, 13, 14, and 15

So, there are 5 numbers out of 15 to get a probability of 2-digit number

Hence, The probability is :

$\sf \to \frac{6}{15} \\ \: or, \to \frac{2}{5}$

❐ In case of (b) :

➡ Number divisible by 3 between 1 to 15 are :

= 3, 6, 9, 12, and 15

So, there are 5 numbers divisible by 3 between 1 to 15.

Hence, The probability is :

$\sf \to \frac{1}{3}$

Formula used in both the cases :

$\bigstar{ \underline{ \boxed{ \sf{probability = \frac{favourable \: outcomes}{total \: outcomes} }}}} \bigstar$

Note behind :

• Here, using the formula of probability we have first counted the favourable outcomes.
• So, in case of (a) the favourable outcomes of getting 2-digit numbers are 10, 11, 12, 13, 14, and 15 which is 6.
• And also, in case of (b) the favourable outcomes of getting numbers divisible by 3 are : 3, 6, 9, 12, and 15 which is 5.