Question

fifteen cards numbered 1,2,3,4.......,15 are put in a box and mixed thoroughly.one card is drawn from the box.what is the probability that number on the card is :
even
a prime
divisible by 3
divisible by 2
divisible by 5
​pls tell guys.
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Answer 1

Answer:

1. 7/15

2. 6/15

3. 5/15 = 1/3

4. 7/15

5. 3/15=1/5

Step-by-step explanation:

$1. \: total \: number \: of \: cards \: n(t) = 15 \\ number \: of \:even \: cards \: n(s)= 7 \\ p(the \: number \: on \: the \: card \: is \: even) = \frac{n(s)}{n(t)} = \frac{7}{15} \\ 2. \: total \: number \: of \: cards \: n(t) = 15 \\ number \: of \:prime \: number \: cards \: n(s)= 6 \: \\ p(the \: number \: on \: the \: card \: is \: a \: prime) = \frac{n(s)}{n(t)} = \frac{6}{15} \\ 3. \: total \: number \: of \: cards \: n(t) = 15 \\ number \: of \: \: cards \: divisible \: by \: 3 \: n(s)= 5 \\ p(the \: number \: on \: the \: card \: is \: divisible \: by\: 3) = \frac{n(s)}{n(t)} = \frac{5}{15} = \frac{1}{3} \\ 4. \: total \: number \: of \: cards \: n(t) = 15 \\ number \: of \: cards \: \: divisible \: by \: 2 \: \: n(s)= 7 \\ p(the \: number \: on \: the \: card \: is \: divisible \: by \: 2) = \frac{n(s)}{n(t)} = \frac{7}{15} \\ 5.\: total \: number \: of \: cards \: n(t) = 15 \\ number \: of \: cards \: \: divisible \: by \: 5 \: \: n(s)= 3 \\ p(the \: number \: on \: the \: card \: is \: divisible \: by \: 5) = \frac{n(s)}{n(t)} = \frac{3}{15} = \frac{1}{5}$