Math, asked by Bhumika00, 9 months ago

fifteen times a number added to half the number which gives 62

Answers

Answered by vasudevsagar7396
15

Answer:

let the unknown number be x

15×x+1/2=62

15x+1/2=62

transport 1/2 to RHS side

15x=62-1/2

take lcm of 1 and 2 =2

15x=(62×2-1)/2

15x=(124-1)/2

15x=123/2

transport 15 RHS.

x=123/2×15

x=123/30

Answered by payalchatterje
3

Complete question is "fifteen times a number added to half the number which gives 62.Then find the number ?"

Answer:

Required number is 4.

Step-by-step explanation:

Given, fifteen times a number added to half the number which gives 62.

Let the number be x.

Now,Fifteen times the number  = 15 \times x

and half the number  =  \frac{x}{2}

Now according to question,

15x +  \frac{x}{2}  = 62 \\  \frac{15x \times 2 + x}{2}  = 62 \\  \frac{30x + x}{2}  = 62 \\  \frac{31x}{2}  = 62 \\ 31x = 62 \times 2 \\ x =  \frac{62 \times 2}{31}  \\ x = 2 \times 2 \\ x = 4

So, required number is 4.

This is a problem of equation solving part of Algebra.

Some important Algebra formulas:

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Equation related two more problems:

https://brainly.in/question/24791936

https://brainly.in/question/48877157

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