Question

Fifteen years later,a man will be two times as old as he was 15 years ago.How old is he now?

Answer 1

Let the age of man be x
A/Q
x+15=2(x-15)
x+15=2x-30
x-2x=-30-15
-x=-45
x=45

Answer 2

$\textbf{\underline{Answer :-}}$

The present age of the man is 45 years.

$\textbf{\underline{Explanation :-}}$

$\textsf{\underline{Given :-}}$

15 years later : Man will be twice of he was 15 years ago.

$\textsf{\underline{To Find :-}}$

His present age

$\textsf{\underline{Solution :-}}$

Consider the man's age as x

$\tt{\implies x +15= 2(x - 15)}$

$\tt{\implies \: x + 15 = 2x - 30}$

$\tt{\implies \: x - 2x = - 30 - 15}$

$\tt{\implies - x = - 45}$

$\tt{\implies{\cancel{ - }}x = {\cancel{ - }}45}$

$\tt{\implies \: x = 45}$

Therefore the present age of the man is 45 years.

$\textbf{\underline{Verification :-}}$

$\tt{\implies45 + 15 = 2(45 - 15)}$

$\tt{\implies60 = 90 - 30}$

$\tt{\implies60 = 60}$

$\therefore$LHS = RHS

$\therefore$The present age of the man is 45 years.