Math, asked by maheshrokade4184, 5 months ago


Fifteen years later, a man will be two times as old as he was 15 years ago. How c'd is he now?

Answers

Answered by Anonymous
6

ANSWER:

Let the present age of the man be x years.

Age of the man 15 years ago =(x−15) years and

Age of the man 15 years later =(x+15) years

According to the given condition, we have

(x+15)=2(x−15)

⇒x+15=2x−30

⇒x−2x=−30−15

⇒−x=−45

or x=45 years

Hence, the present age of the man is 45 years

hope it helps........★

Answered by taqueerizwan2006
0

Step-by-step explanation:

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Let the present age of the man be x years.

Age of the man 15 years ago =(x−15) years and

Age of the man 15 years later =(x+15) years

According to the given condition, we have

(x+15)=2(x−15)

⇒x+15=2x−30

⇒x−2x=−30−15

⇒−x=−45

or x=45 years

Hence, the present age of the man is 45 years

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