Question

fifth,8 and 11 term of a geometric expression are p q and R respectively .show that Q square is equal to PR ​

Answer 1

Answer:

Step-by-step explanation:

let first term of geometric progression be "a"

and common ratio be "k"

then 5th term is a$k^{10}$ =p

8th term is  a$k^{7}$ =q

11 th is a$k^{10}$=r

perform the desired expression you will get the ans

$q^{2}=pr$