Question

fifth root of fourth power of 27 please tell me my test​

Answer 1

$\sqrt[5]{ {27}^{4} }$

$= \sqrt[5]{(27 \times 27 \times 27 \times 27} )$

$= \sqrt[5]{( { {3}^{3} })^{4} }$

$= \sqrt[5]{ {3}^{12} }$

$= {3}^{ \frac{12}{5} }$