Fifth term of H.P 2, 2 1/2, 3 1/3 ...
Answers
Given:
H.P 2, 2 1/2, 3 1/3 ...
To find:
Fifth term of H.P 2, 2 1/2, 3 1/3 ...
Solution:
From given, we have,
H.P 2, 2 1/2, 3 1/3 ...
upon simplifying, we get,
H.P 2, 5/2, 10/3
Thus the series in A.P is given as
A.P. 1/2, 2/5, 3/10
the first term is, a = 1/2
the common difference is, d = 3/5 - 1/2 = - 1/10
we use the formula for calculating the nth term,
tn = a + (n - 1) d
t5 = 1/2 + (5 - 1) (-1/10)
t5 = 1/2 + 4 (-1/10)
t5 = 1/2 - 2/5
t5 = 1/10
Thus the fifth term of A.P. is 1/0
Therefore, the 5th term of the H.P. is 10
Given:
H.P 2, 2 1/2, 3 1/3 ...
To find:
Fifth term of H.P 2, 2 1/2, 3 1/3 ...
Solution:
From given, we have,
H.P 2, 2 1/2, 3 1/3 ...
upon simplifying, we get,
H.P 2, 5/2, 10/3
Thus the series in A.P is given as
A.P. 1/2, 2/5, 3/10
the first term is, a = 1/2
the common difference is, d = 3/5 - 1/2 = - 1/10
we use the formula for calculating the nth term,
tn = a + (n - 1) d
t5 = 1/2 + (5 - 1) (-1/10)
t5 = 1/2 + 4 (-1/10)
t5 = 1/2 - 2/5
t5 = 1/10
Thus the fifth term of A.P. is 1/0
Therefore, the 5th term of the H.P. is 10