Question

Fig. 1.15 below shows the reading obtained while measuring the diameter of a wire with a screw
gauge. The screw advances by 1 division on main scale when circular head is rotated once.
Find: i) pitch of the screw gauge.
ii) least count of the screw gauge
iii) the diameter of the wire.​

Answer 1

Answer:

As the he number of divisions on main scale are 10 to a centimeter, so the smallest division on main scale will be 1mm and it will be the pitch (p) of the screw gauge. The number of circular divisions is n=100.

The least count of a screw gauge is L.C=p/n=1mm/100=0.01mm=(0.01/10)cm=0.001cm=10

−3

cm

Explanation:

w