Fig. 1.31 shows two forces each of magnitude 10 N
acting at points A and B at a separation of 50 cm, in
opposite directions. Calculate the resultant
moment of the two forces about the point (i) A, (ii) B
and (iii) O situated exactly at the middle of the two
forces.
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Answers
Fig. 1.31 shows two forces each of magnitude 10 N acting at points A and B at a separation of 50 cm, in opposite directions.
Given,
Force at A in upward direction = F = 10 N
Force at B in downward direction = F = 10 N
Distance between the points A and B = 50 cm = 0.5 m
(i) The resultant moment of the two forces about the point A
= 10 N × 0.5 m
= 5 Nm in clockwise direction.
(ii) The resultant moment of the two forces about the point B
= 10 N × 0.5 m
= 5 Nm in clockwise direction.
(iii) O situated exactly at the middle of the two forces.
At point O, the perpendicular distance from either of the forces F = 10 N is 0.5/2 = 0.25 m.
The moment of the two forces at the point A about O
= 10 N × 0.25 m
= 2.5 Nm in clockwise direction.
The moment of the two forces at the point B about O
= 10 N × 0.25 m
= 2.5 Nm in clockwise direction.
Therefore, the moment of the two forces about O
= 2.5 Nm + 2.5 Nm
= 5 Nm in clockwise direction.
Answer:
Step-by-step explanation:
As you can see that the movement is clockwise.
i) Moment of force A: 10N×0.5m=5Nm clockwise
ii) Moment of force B:
10N× 0.5m=5Nm clockwise
iii) In this part of the question we have to be clear that the answer is asked about the perpendicular distance between A and B.
The perpendicular distance between = 0.5/2=0.25
Now,
Moment of force A:
10N×0.5m=2.5Nm clockwise
Moment of force B:
10N× 0.5m=2.5Nm clockwise
The moment of force exact at the middle of the two forces:
2.5Nm+2.5Nm= 5Nm clockwise